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0.02x^2-10x=10000
We move all terms to the left:
0.02x^2-10x-(10000)=0
a = 0.02; b = -10; c = -10000;
Δ = b2-4ac
Δ = -102-4·0.02·(-10000)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-30}{2*0.02}=\frac{-20}{0.04} =-500 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+30}{2*0.02}=\frac{40}{0.04} =1000 $
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